解法:用filter即可
JavaScript
/**
* @param {number[]} nums
* @return {number[]}
*/
var smallerNumbersThanCurrent = function (nums) {
if (nums.length < 2 || nums.length > 500) {
return;
}
let temp = [];
nums.forEach((v) => {
const count = nums.filter(i => i < v).length
temp.push(count);
});
return temp;
};